Saturday, July 22, 2006

All Numbers Are Equal

 
Theorem: All numbers are equal.
 
Proof: Choose arbitrary a and b, and let t = a + b.
 
Then

a + b = t
(a + b)(a - b) = t(a - b)
a^2 - b^2 = ta - tb
a^2 - ta = b^2 - tb
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
(a - t/2)^2 = (b - t/2)^2
a - t/2 = b - t/2
a = b

So all numbers are the same, and math is pointless.

0 responses:

Post a Comment

Thanking you for your comment(s). Hope you will visit this blog again!

Subscribe to geeklog feed Bookmark and Share

Design by Free blogger template